Woodson Wins Defensive Player of the Year By a Landslide

It's time to celebrate

Green Bay Packers cornerback Charles Woodson put the question to rest today. He’s the NFL Defensive Player of the Year and he won by a wide margin over New York Jets’ cornerback Darrelle Revis.

Woodson received 28 votes to Revis’ 14. The Denver Broncos’ Elvis Dumervil and the New Orleans Saints’ Darren Sharper tied for third with three votes. The Minnesota Vikings’ Jared Allen got two votes.

“Any time you go out there on the field, you go out there to win the game, of course,” Woodson said, “but you go out there to be consistent and a reliable player. And that’s what that award is. You go out there, you can make plays and can continue to make them through the season and you’re mentioned as far as being Defensive Player of the Year, you know you’re doing some things right.”

Although there has been some debate, Woodson clearly had the best season of any defensive player in the NFL and was justly awarded for it – something we predicted in early December. Woodson won the NFC Defensive Player of the Month three times this season.

At 33, he finished off his best season as a pro with the following line – 74 tackles, 9 interceptions, 2 sacks, 4 forced fumbles, 3 touchdowns.

“I’ve said it before, he’s had two or three games that I can’t imagine any defensive player in the league having better games,” said Packers defensive coordinator Dom Capers, who also coached Rod Woodson (1993) and Jason Taylor (2006) when they won the award. “I think it speaks volumes when he was player of the month in September and came back and got player of the month again [in November].”

Indeed.

Congratulations, Charles.

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